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Kp = Kc × (RT)n  |  R = 0.082057 (atm)
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Understanding Equilibrium Constants: Kp and Kc

In reversible chemical reactions, the equilibrium state can be described by an equilibrium constant, which can be expressed either in terms of molar concentration (Kc) or in terms of partial pressure (Kp). The Equilibrium Constant Calculator and Kp to Kc Converter tool simplifies the conversion between these two forms, allowing you to quickly obtain the correct value for your reaction.

The Concentration-Based Constant Kc

For a general reaction:

aA+bB⇌cC+dDaA + bB \rightleftharpoons cC + dD

the equilibrium constant in terms of concentration is:

Kc=[C]c[D]d[A]a[B]bK_c = \frac{[C]^c [D]^d}{[A]^a [B]^b}

where [A][A] and [B][B] are the molar concentrations of the reactants, and [C][C] and [D][D] are the molar concentrations of the products. The Chemical Equilibrium Calculator on this page automatically handles these expressions.

The Partial-Pressure Constant Kp

When dealing with gases, it is often more convenient to measure partial pressures. The equilibrium constant in terms of partial pressure follows an analogous form:

Kp=PCcPDdPAaPBbK_p = \frac{P_C^c P_D^d}{P_A^a P_B^b}

where PAP_A and PBP_B are the partial pressures of the gaseous reactants, and PCP_C and PDP_D are those of the gaseous products.

The Relationship Between Kp and Kc

The conversion between Kp and Kc uses the equation:

Kp=Kc⋅(R⋅T)ΔnK_p = K_c \cdot (R \cdot T)^{\Delta n}

where:

  • RR is the universal gas constant,
  • TT is the absolute temperature (in Kelvin),
  • Δn\Delta n is the change in the number of moles of gas, defined as:
Δn=(moles of gaseous products)−(moles of gaseous reactants)\Delta n = (\text{moles of gaseous products}) - (\text{moles of gaseous reactants})

If Δn=0\Delta n = 0, then Kp equals Kc directly. For any other value, you can rely on the Kp Calculator to compute the conversion quickly and accurately.

Step-by-Step Conversion Example (Haber Process)

Consider the synthesis of ammonia:

N2(g)+3H2(g)⇌2NH3(g)N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g)

At 298 K, the equilibrium constant Kc is 2.27×10−22.27 \times 10^{-2}. To find Kp:

  1. Choose the correct gas constant according to the pressure unit you intend to use. For atmospheres, R=0.082057 L⋅atm⋅K−1⋅mol−1R = 0.082057 \ \text{L·atm·K}^{-1}\text{·mol}^{-1}.
  2. Calculate Δn\Delta n:
    Δn=2−(3+1)=−2\Delta n = 2 - (3 + 1) = -2.
  3. Apply the formula: Kp=2.27×10−2×(0.082057×298)−2K_p = 2.27 \times 10^{-2} \times (0.082057 \times 298)^{-2} This yields Kp≈3.796×10−5K_p \approx 3.796 \times 10^{-5}.

The same procedure works for any gaseous reaction; just ensure you only include species in the gas phase.

Important Considerations

  • Only gases matter: In heterogeneous reactions, solids and liquids do not appear in the Kp expression. For example, in the reaction 2H2(g)+O2(g)⇌2H2O(s)2H_2(g) + O_2(g) \rightleftharpoons 2H_2O(s), the Kp expression is simply: Kp=1PH22⋅PO2K_p = \frac{1}{P_{H_2}^2 \cdot P_{O_2}}
  • Unit consistency is crucial. The table below lists the most common pressure units and their corresponding gas constants for the Kp–Kc conversion.
Pressure unitGas constant R value (typical)Gas constant unit
atm0.082057L·atm·K⁻¹·mol⁻¹
kPa8.31446L·kPa·K⁻¹·mol⁻¹
bar0.083145L·bar·K⁻¹·mol⁻¹
Torr62.3637L·Torr·K⁻¹·mol⁻¹
mmHg62.3637L·mmHg·K⁻¹·mol⁻¹

Using the Partial Pressure Calculator ensures these constants are applied correctly, so you can focus on your chemical equilibrium problem without manual unit conversions.

Summary

Whether you need to convert Kc to Kp or vice versa, the fundamental relationship Kp=Kc(RT)ΔnK_p = K_c (RT)^{\Delta n} is your guide. With the Kp to Kc Converter and the information above, you can handle any reversible gaseous reaction efficiently. Remember to verify your units and to include only gaseous species in the equilibrium expression.

FAQ

1. How do I convert Kc to Kp?

Use the equation Kp = Kc * (R * T)^(Δn), where Δn is the difference between the sum of gaseous product coefficients and the sum of gaseous reactant coefficients. Select the gas constant R that matches your pressure unit (e.g., 0.082057 L·atm/K·mol for atm). If Δn = 0, Kp equals Kc.

2. What does Δn represent and how is it calculated?

Δn is the change in the number of moles of gas during the reaction. It is calculated as: Δn = (moles of gaseous products) - (moles of gaseous reactants). For example, in N₂ + 3H₂ ⇌ 2NH₃, Δn = 2 - (3+1) = -2.

3. Why are solids and liquids omitted from the Kp expression?

Kp is defined in terms of partial pressures of gases. Solids and liquids have constant activity (effectively 1) and do not appear in the equilibrium expression for gases. Therefore, only gaseous species are included when writing Kp.

4. Are Kp and Kc always the same numerical value?

No. They are related by Kp = Kc (RT)^(Δn). If Δn = 0 (no change in the number of gas moles), then Kp = Kc. Otherwise, the values differ due to the (RT)^(Δn) factor.

How to Use

  1. Select the calculation mode: convert Kp to Kc or Kc to Kp.
  2. Enter the known equilibrium constant, temperature, and change in moles of gas (Δn).
  3. Click Calculate to get the converted equilibrium constant.