Free Horizontal Projectile Motion Calculator

Enter any 2 values to see results

Understanding Horizontal Projectile Motion

This horizontal projectile motion calculator is designed to handle the specific scenario where an object is launched with a purely horizontal initial velocity from an elevated point. By entering just two known values—such as launch speed and height—you instantly obtain the projectile’s time of flight, horizontal range, and the complete trajectory. The tool complements a projectile range calculator and a time of flight calculator by focusing on the zero‑angle case, making it ideal for homework problems and quick physics checks.

In this type of motion, the launch angle is zero because the velocity is parallel to the ground. Consequently, the initial vertical velocity is zero, and the only acceleration acting on the projectile is gravity (g≈9.8 m/s2g \approx 9.8\ \text{m/s}^2 downward). The motion is therefore a combination of constant‑velocity horizontal motion and uniformly accelerated vertical motion.

Key Equations for Horizontal Projectile Motion

To keep the mathematics simple, place the origin at the ground directly below the launch point. If the launch height is hh and the initial speed is VV, then:

  • Horizontal displacement (at time tt):
x(t)=Vtx(t) = V t
  • Vertical displacement (measured upward from the ground):
y(t)=h−12gt2y(t) = h - \frac{1}{2} g t^{2}

The projectile hits the ground when y=0y = 0. Solving h−12gt2=0h - \frac{1}{2} g t^{2} = 0 gives the time of flight:

tflight=2hgt_{\text{flight}} = \sqrt{\frac{2h}{g}}

The horizontal range (also called the projectile range) follows directly:

R=V⋅tflight=V2hgR = V \cdot t_{\text{flight}} = V \sqrt{\frac{2h}{g}}

Eliminating tt between the xx and yy equations yields the trajectory equation (a parabola):

y=h−g2V2x2y = h - \frac{g}{2V^{2}} x^{2}

This is a much simpler expression than the general projectile trajectory formula, because the launch angle is fixed at 0∘0^{\circ}. The physics trajectory calculator embedded in this tool plots this parabolic curve for you.

Key Properties

  • Horizontal velocity remains constant throughout the flight: vx=Vv_x = V.
  • Vertical velocity increases linearly downward: vy=−gtv_y = -g t.
  • Horizontal acceleration is zero.
  • Vertical acceleration is constant: −g-g.
  • Because air resistance is neglected, mechanical energy is conserved (kinetic plus gravitational potential).

Note that the maximum height reached is simply the initial launch height hh, since there is no upward vertical component.

Worked Example: Throwing a Ball from the Eiffel Tower

Suppose you throw a ball horizontally at 7 m/s7\ \text{m/s} from the upper platform of the Eiffel Tower, which is 276 m276\ \text{m} above the ground.

  1. Set the velocity to 7 m/s7\ \text{m/s}.
  2. Set the initial height to 276 m276\ \text{m}.
  3. The horizontal projectile motion calculator instantly returns:
    • Time of flight: 2×276/9.8≈7.5 s\sqrt{2 \times 276 / 9.8} \approx 7.5\ \text{s}
    • Horizontal range: 7×7.5≈52.5 m7 \times 7.5 \approx 52.5\ \text{m}

You can also use the tool in reverse: for a desired range of 100 m100\ \text{m}, find the required launch speed from the same height.

Using the Calculator Effectively

The calculator accepts any two of the three main variables—velocity, height, and range—and fills in the missing ones. This flexibility makes it a practical horizontal velocity calculator and a powerful aid for exploring projectile motion. Whether you are a student verifying textbook problems or a hobbyist estimating real‑world throws, the tool automatically handles unit conversions and displays the trajectory graph.

FAQ

1. How do I calculate the horizontal distance (range) of a projectile launched horizontally?

Use the formula R = V × sqrt(2h/g), where V is the initial horizontal velocity, h is the launch height, and g is 9.8 m/s². Alternatively, the horizontal projectile motion calculator can compute it directly if you enter any two of the three values (velocity, height, range).

2. What is the time of flight for a horizontally launched projectile?

The time of flight depends only on the height from which the object is dropped: t = sqrt(2h/g). It is independent of the horizontal speed. For example, from 276 m it takes about 7.5 seconds.

3. Is there any horizontal acceleration in horizontal projectile motion?

No, the horizontal acceleration is zero. Gravity acts only vertically, so the horizontal velocity remains constant throughout the entire motion (ignoring air resistance).

4. What is the vertical acceleration of a projectile when it is launched horizontally?

The vertical acceleration is constant and equal to g (approximately 9.8 m/s²) directed downward. There is no initial vertical velocity, but gravity accelerates the projectile downward from the start.

5. How does the trajectory of a horizontally launched projectile look like?

The path is a parabola. Its equation is y = h - (g/(2V^2)) x², where V is the initial speed and h is the height. The peak of the trajectory is at the launch point because there is no upward vertical component.

How to Use

  1. Enter any two values among velocity, initial height, time of flight, or horizontal distance with their units.
  2. The calculator automatically determines the remaining values using horizontal projectile motion equations.
  3. Read the computed results including impact velocity and angle for your projectile.