Free Projectile Range Calculator

d = v₀cos(α) × (v₀sin(α) + √[(v₀sin(α))² + 2gh]) / g

Enter velocity, launch angle, and initial height to calculate projectile range

About the Projectile Range Calculator

The Projectile Range Calculator is a free online tool for quickly determining the horizontal displacement of an object undergoing projectile motion. As a dedicated physics projectile range tool, it requires only three inputs —initial velocity, launch angle, and launch height— to compute the range of projectile. This makes it an ideal horizontal displacement calculator for students, teachers, and anyone working in physics or ballistics. The calculations assume a vacuum (no air resistance) to focus on ideal projectile motion.

Projectile Range Formulas

The formula for the range of a projectile depends on whether the launch occurs from ground level (zero initial height) or from an elevated position.

Launch from the Ground (Initial Height = 0)

When an object is launched from the ground and lands at the same elevation, the vertical displacement at landing is zero. Starting from the kinematic equation for vertical motion:

0=V0sin⁡(α)⋅t−12gt20 = V_0 \sin(\alpha) \cdot t - \frac{1}{2} g t^{2}

Solving for the time of flight tt gives:

t=2V0sin⁡(α)gt = \frac{2 V_0 \sin(\alpha)}{g}

The horizontal velocity remains constant at V0cos⁡(α)V_0 \cos(\alpha), so the horizontal range dd is:

d=V0cos⁡(α)⋅t=V0cos⁡(α)⋅2V0sin⁡(α)g=2V02sin⁡(α)cos⁡(α)gd = V_0 \cos(\alpha) \cdot t = V_0 \cos(\alpha) \cdot \frac{2 V_0 \sin(\alpha)}{g} = \frac{2 V_0^{2} \sin(\alpha) \cos(\alpha)}{g}

Using the identity sin⁡(2α)=2sin⁡(α)cos⁡(α)\sin(2\alpha) = 2\sin(\alpha)\cos(\alpha), the formula simplifies to:

d=V02sin⁡(2α)gd = \frac{V_0^{2} \sin(2\alpha)}{g}

From this expression, the maximum range occurs when sin⁡(2α)=1\sin(2\alpha) = 1, i.e., 2α=90∘2\alpha = 90^\circ or α=45∘\alpha = 45^\circ.

Launch from an Elevation (Initial Height > 0)

If the projectile is launched from a height hh above the landing point, the vertical motion equation becomes:

h+V0sin⁡(α)⋅t−12gt2=0h + V_0 \sin(\alpha) \cdot t - \frac{1}{2} g t^{2} = 0

Solving this quadratic for tt yields the time of flight:

t=V0sin⁡(α)+(V0sin⁡(α))2+2ghgt = \frac{V_0 \sin(\alpha) + \sqrt{\left(V_0 \sin(\alpha)\right)^{2} + 2 g h}}{g}

The horizontal range is then:

d=V0cos⁡(α)⋅t=V0cos⁡(α)⋅V0sin⁡(α)+(V0sin⁡(α))2+2ghgd = V_0 \cos(\alpha) \cdot t = V_0 \cos(\alpha) \cdot \frac{V_0 \sin(\alpha) + \sqrt{\left(V_0 \sin(\alpha)\right)^{2} + 2 g h}}{g}

This is the general formula used by the projectile range calculator when a non‑zero initial height is provided.

Example: Volcanic Ejection

Consider a rock ejected from a volcano with an initial speed of 30 m/s30 \, \text{m/s} at an angle of 25∘25^\circ. The launch point is 100 m higher than the landing area. Using the elevated launch formula:

d=30cos⁡(25∘)⋅30sin⁡(25∘)+(30sin⁡(25∘))2+2⋅9.81⋅1009.81≈162.87 md = 30 \cos(25^\circ) \cdot \frac{30 \sin(25^\circ) + \sqrt{(30 \sin(25^\circ))^2 + 2 \cdot 9.81 \cdot 100}}{9.81} \approx 162.87 \, \text{m}

The calculator instantly provides this result, demonstrating how even a moderate launch angle and height can produce a substantial horizontal reach.

Important Considerations

  • Air resistance is neglected in all calculations. In reality, drag reduces the projectile range, and its effect depends on the object’s shape, cross‑section, and surface properties.
  • The initial height greatly influences the range; a higher launch point gives a longer flight time and a larger horizontal displacement, assuming the same initial speed and angle.
  • The calculator accepts any consistent units (meters, feet, etc.), but the standard unit for range is meters in physics contexts.

FAQ

1. What parameters are needed to calculate projectile range?

You need the initial velocity, launch angle, and launch height relative to the landing point. The calculator uses these to compute the horizontal displacement.

2. What is the formula for projectile range when launching from ground level?

For ground launches, the range is \(d = V_0^2 \sin(2\alpha) / g\), where \(V_0\) is the initial speed, \(\alpha\) is the launch angle, and \(g\) is gravitational acceleration.

3. How does launch height affect projectile range?

A higher launch height increases the time of flight, resulting in a longer horizontal range for the same speed and angle. The calculator uses the elevated launch formula to account for this.

4. What is the best angle to maximize projectile range?

In an ideal vacuum, the maximum range occurs at a 45° launch angle because \(\sin(2\alpha)\) reaches its maximum value of 1 at \(2\alpha = 90°\).

5. Does the projectile range calculator consider air resistance?

No, the calculator assumes a vacuum without air resistance. In real-world conditions, drag would reduce the range based on the object’s shape and other factors.

How to Use

  1. Enter the initial velocity of the projectile and select the appropriate velocity unit (m/s, km/h, ft/s, or mph).
  2. Set the launch angle in degrees or radians and optionally provide the initial launch height from which the projectile is launched.
  3. The horizontal range of the projectile is calculated instantly using the projectile motion formula.