Free Maximum Height Calculator - Projectile Motion

h_max = h₀ + (v₀² · sin²(α)) / (2g)

Enter velocity, launch angle, and initial height to calculate maximum height

Understanding Maximum Height in Projectile Motion

In projectile motion, the maximum height of an object is the highest vertical point it reaches along its trajectory. This concept is fundamental in physics and is essential for analyzing the motion of projectiles such as balls, arrows, or rockets. Whether you're working on a physics problem or designing a launch, a projectile motion calculator can quickly determine the maximum height of projectile based on initial velocity, launch angle, and starting elevation.

The Physics Behind Maximum Height

At the apex of a projectile's flight, its vertical velocity becomes zero (vy=0v_y = 0). This moment occurs exactly when the upward motion stops and the downward fall begins. Using basic kinematic equations, we can calculate the time it takes to reach that peak:

th=v0sin⁡αgt_h = \dfrac{v_0 \sin\alpha}{g}

where v0v_0 is the initial velocity, α\alpha is the launch angle (measured from the horizontal), and gg is the gravitational acceleration (≈ 9.8 m/s29.8\ \text{m/s}^2 or 32.2 ft/s232.2\ \text{ft/s}^2).

Formula for Maximum Height

The vertical displacement equation gives the relationship between height, initial position, and time. Plugging in tht_h and setting the final vertical velocity to zero yields the classic launch height calculator formula:

hmax⁡=h0+v02sin⁡2α2gh_{\max} = h_0 + \dfrac{v_0^2 \sin^2\alpha}{2g}

Here h0h_0 is the initial elevation (if any). When the projectile starts from ground level, h0=0h_0 = 0, and the equation simplifies to hmax⁡=v02sin⁡2α2gh_{\max} = \dfrac{v_0^2 \sin^2\alpha}{2g}.

Adjusting for an Initial Height

If the projectile is launched from a raised platform, hilltop, or any non-zero starting height, simply add that value to the computed vertical rise. The formula above already accounts for this—just enter the initial height into the physics projectile height calculator, and it will incorporate the extra distance.

How Launch Angle Affects the Maximum Height

The launch angle plays a decisive role in determining the peak altitude:

  • α = 90° (vertical launch): The projectile goes straight up and reaches its greatest possible height for a given speed. The formula reduces to hmax⁡=h0+v022gh_{\max} = h_0 + \dfrac{v_0^2}{2g}. This also yields the longest flight time.
  • α = 45°: The projectile splits its velocity equally between horizontal and vertical components. The maximum height becomes hmax⁡=h0+v024gh_{\max} = h_0 + \dfrac{v_0^2}{4g}. When launched from the ground, this angle maximizes the horizontal range.
  • α = 0° (horizontal launch): Since sin⁡0=0\sin 0 = 0, there is no vertical component of initial velocity. The projectile immediately begins falling, so its maximum height is simply the initial height h0h_0 (the starting elevation). This case is often called horizontal projectile motion.

Using the Maximum Height Calculator

This maximum height calculator is designed for quick, accurate results. You input the projectile's initial velocity, launch angle, and optionally the initial height. The tool instantly returns the peak altitude. For example, launching a ball with a velocity of 30 ft/s30\ \text{ft/s} at an angle of 70∘70^\circ from ground level produces a maximum height of approximately 12.35 ft12.35\ \text{ft}. You can then decide whether the object can clear a barrier or adjust parameters to meet a specific goal.

Important: The calculator assumes ideal conditions—no air resistance. In real-world scenarios, friction would reduce the height and range, but the equations above describe the pure physics of projectile motion.

By combining the projectile motion calculator with an understanding of these principles, you can quickly analyze any launched object's trajectory.

FAQ

1. How do I calculate the maximum height of a projectile?

Use the formula \(h_{\max} = h_0 + \frac{v_0^2 \sin^2\alpha}{2g}\). Input the initial velocity \(v_0\), launch angle \(\alpha\), and starting height \(h_0\); then plug in the gravitational acceleration \(g\) (≈ 9.8 m/s²).

2. Does the mass of the projectile affect its maximum height?

No, the maximum height depends only on initial velocity, launch angle, and starting elevation. Mass does not appear in the projectile motion equations (ignoring air resistance).

3. What angle gives the highest maximum height?

A launch angle of 90° (straight up) gives the greatest height for a given velocity, because all the initial speed goes into the vertical component.

4. Can the calculator handle projectiles launched from a height above ground?

Yes, simply enter the initial elevation (h₀) into the calculator. The formula adds that value to the vertical rise computed from velocity and angle.

5. What is the maximum height when the launch angle is 0°?

At 0°, the projectile has no vertical velocity, so it never rises above its starting point. Thus the maximum height equals the initial height (h₀).

How to Use

  1. Enter the initial velocity of the projectile and select the appropriate velocity unit (m/s, km/h, ft/s, or mph).
  2. Set the launch angle in degrees or radians and optionally provide the initial launch height.
  3. The maximum height of the projectile is calculated instantly using the projectile motion formula.